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0=-0.01x^2+25x-15525
We move all terms to the left:
0-(-0.01x^2+25x-15525)=0
We add all the numbers together, and all the variables
-(-0.01x^2+25x-15525)=0
We get rid of parentheses
0.01x^2-25x+15525=0
a = 0.01; b = -25; c = +15525;
Δ = b2-4ac
Δ = -252-4·0.01·15525
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-2}{2*0.01}=\frac{23}{0.02} =1150 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+2}{2*0.01}=\frac{27}{0.02} =1350 $
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